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Established Member
Join Date: Jun 2006
Posts: 2,866
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Here it is,
weigh 6 - three from each side. if they are equal, we know how that plays out. But if they are not equal, then weigh three from the low (heavy) side against 3 of the 5 remaining (which we know are all equal because the oddball is somewhere in the unbalanced ones). Now, that's two weighings. and there are two scenarios here. 1. if they are equal, then you weigh 2 of the three from the light side If those are equal then the 3rd from that side is the oddball. if not, then the light one is. 2. if unequal, then weigh 2 from the heavy side. If equal, the the oddball is heavy. if unequal, the heavy one is. And my head hurts now... C
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